In a parallelogram ABCD,angle A = 5 angle B,t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a parallelogram $ABCD$,the sum of adjacent angles is $180^o$. Therefore,$\angle A + \angle B = 180^o$.Given that $\angle A = 5 \angle B$,we sub

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(A) In a parallelogram $ABCD$,the sum of adjacent angles is $180^o$. Therefore,$\angle A + \angle B = 180^o$.Given that $\angle A = 5 \angle B$,we substitute this into the equation:$5 \angle B + \angle B = 180^o$$6 \angle B = 180^o$$\angle B = 30^o$.Since $\angle A = 5 \angle B$,then $\angle A = 5 	imes 30^o = 150^o$.In a parallelogram,opposite angles are equal,so $\angle C = \angle A$.Therefore,$\angle C = 150^o$.

In a parallelogram $ABCD$,$\angle A = 5 \angle B$,then $\angle C = \ldots$ (in $^o$)

Similar Questions

In the figure,$ABCD$ and $AEFG$ are two parallelograms. If $\angle C = 55^{\circ},$ determine $\angle F.$ (in $^{\circ}$)

Prove that the line segment joining the midpoints of two opposite sides of a parallelogram divides the parallelogram into two parallelograms with equal area.

$ABCD$ is a parallelogram. If its diagonals are equal,then find the value of $\angle ABC$. (in $^{\circ}$)

Show that each angle of a rectangle is a right angle.

In parallelogram $ABCD$,$AB = 12 \, cm$. Altitudes $DM$ and $DN$ correspond to bases $AB$ and $BC$ respectively. If $DM = 5 \, cm$ and $DN = 6 \, cm$,then find the length of $BC$ in $cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module