In parallelogram ABCD,AB = 12 , cm. Altitudes | vedclass

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(B) The area of a parallelogram is the product of its base and the altitude corresponding to that base.In parallelogram $ABCD$,the area can be calcula

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$10$

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(B) The area of a parallelogram is the product of its base and the altitude corresponding to that base.In parallelogram $ABCD$,the area can be calculated using base $AB$ with altitude $DM$,or base $BC$ with altitude $DN$.Therefore,$	ext{Area}(ABCD) = AB 	imes DM = BC 	imes DN$.Given $AB = 12 \, cm$,$DM = 5 \, cm$,and $DN = 6 \, cm$.Substituting these values: $12 	imes 5 = BC 	imes 6$.$60 = BC 	imes 6$.$BC = \frac{60}{6} = 10 \, cm$.

In parallelogram $ABCD$,$AB = 12 \, cm$. Altitudes $DM$ and $DN$ correspond to bases $AB$ and $BC$ respectively. If $DM = 5 \, cm$ and $DN = 6 \, cm$,then find the length of $BC$ in $cm$.

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