In a photoelectric experiment,light of wavelength $800 \ nm$ produces photoelectrons with the smallest de Broglie wavelength of $1 \ nm$. Then the work function of the metal used in the experiment is nearly (in $eV$)

  • A
    $0.05$
  • B
    $0.53$
  • C
    $2.03$
  • D
    $4.02$

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Similar Questions

By a suitable example,show that the particle or wave nature of light depends on the type of experiment.

The anode voltage of a photocell is kept constant. The wavelength of the incident light on the cathode is changed gradually. Then,the photoelectric current $I$ of the photocell varies according to which of the following graphs?

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. $E = hv$ $I$. de Broglie wavelength
$B$. Diffraction and Interference $II$. Particle nature of light
$C$. $\lambda = h/p$ $III$. Wave nature of light
$D$. Compton effect $IV$. Energy of photon

Choose the correct answer from the options given below:

In a photoelectric effect experiment,three different metal plates $p, q,$ and $r$ have work functions $\phi_p = 2.0 \ eV, \phi_q = 2.5 \ eV,$ and $\phi_r = 3.0 \ eV$. The incident light beams have wavelengths $\lambda_p = 550 \ nm, \lambda_q = 450 \ nm,$ and $\lambda_r = 350 \ nm$. The intensity of light is the same for each plate. The correct $I-V$ graph for the experiment is: $[hc = 1240 \ eV \ nm]$

The anode voltage of a photocell is kept constant. The wavelength of the light incident on the cathode is changed gradually. Which of the following graphs represents the variation of the photoelectric current $(I)$ with the wavelength $(\lambda)$?

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