In a step-up transformer,220 , V is converted | vedclass

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(C) For a transformer,the relationship between the number of turns and the voltage is given by the formula: $\frac{N_s}{N_p} = \frac{V_s}{V_p}$.Given:

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$6000$

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(C) For a transformer,the relationship between the number of turns and the voltage is given by the formula: $\frac{N_s}{N_p} = \frac{V_s}{V_p}$.Given:Primary voltage $V_p = 220 \, V$Secondary voltage $V_s = 2200 \, V$Number of turns in primary coil $N_p = 600$Substituting the values into the formula:$\frac{N_s}{600} = \frac{2200}{220}$$\frac{N_s}{600} = 10$$N_s = 600 	imes 10 = 6000$.Therefore,the number of turns in the secondary coil is $6000$.

In a step-up transformer,$220 \, V$ is converted into $2200 \, V$. The number of turns in the primary coil is $600$. What is the number of turns in the secondary coil?

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