In a transistor,in common emitter configuration,the ratio of power gain to voltage gain is

For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is:

In a common-emitter transistor,the current gain $\beta$ is $49$. If there is a change of $5.0 \ \mu A$ in the base current,what will be the change in the collector current and the emitter current?

$A$ transistor is used as an amplifier in a common-base configuration. The load resistance is $5 \text{ k}\Omega$, the current gain is $0.98$, and the input resistance is $70 \Omega$. The voltage gain and power gain are, respectively:

For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

If $\alpha = 0.98$ and the current through the emitter $i_e = 20 \, mA$,the value of $\beta$ is