In a triangle $ABC$,if $|\overrightarrow{BC}|=3$,$|\overrightarrow{AC}|=5$,and $|\overrightarrow{BA}|=7$,then the projection of the vector $\overrightarrow{BA}$ on $\overrightarrow{BC}$ is equal to:

  • A
    $\frac{11}{2}$
  • B
    $\frac{13}{2}$
  • C
    $\frac{19}{2}$
  • D
    $\frac{15}{2}$

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