In an $LCR$ series circuit, if the potential differences across the inductor, capacitor, and resistor are $60 \,V$, $30 \,V$, and $40 \,V$ respectively, then the $AC$ voltage applied to the circuit is: (in $\,V$)

In the adjoining figure,the impedance of the circuit will be $... \Omega$.

$A$ series $LCR$ circuit consists of an inductor $L$,a capacitor $C$,and a resistor $R$ connected across a source of emf $\varepsilon = \varepsilon_0 \sin \omega t$. When $\omega L = \frac{1}{\omega C}$,the current in the circuit is $I_0$. If the angular frequency of the source is changed to $\omega^{\prime}$,the current in the circuit becomes $\frac{I_0}{2}$. Then,the value of $\left|\omega^{\prime} L - \frac{1}{\omega^{\prime} C}\right|$ is

In a series $LCR$ circuit,the voltages across $R, L$ and $C$ are shown in the figure. The voltage of the applied source is ........ $V$. (in $, V$)

$A$ circuit has three elements: a resistance of $11 \Omega$,a coil of inductive reactance $120 \Omega$,and a capacitive reactance of $120 \Omega$ in series,connected to an $A.C.$ source of $110 \, V, 60 \, Hz$. Which of the three elements has the minimum potential difference?

In the circuit shown in the figure,the $AC$ source provides a voltage $V = 20 \cos(2000t)$. Neglecting source resistance,the voltmeter and ammeter readings will be: