In an atomic reactor,the kinetic energy of fast-moving neutrons can be reduced by colliding them with:

Each nuclear fission of ${}^{235}U$ releases $200 \text{ MeV}$ of energy. If a reactor generates $1 \text{ MW}$ power,then the rate of fission in the reactor is:

Energy released when two deuterons $\left({ }_1 H ^2\right)$ fuse to form a helium nucleus $\left({ }_2 He ^4\right)$ is $:$
(Given $:$ Binding energy per nucleon of ${ }_1 H ^2=1.1 \ \text{MeV}$ and binding energy per nucleon of ${ }_2 He ^4=7.0 \ \text{MeV}$) (in $\text{MeV}$)

The binding energies of nuclei $X$ and $Y$ are $E_1$ and $E_2$ respectively. Two atoms of $X$ fuse to give one atom of $Y$ and an energy $Q$ is released. Then:

Define the multiplication factor $(k)$ in the context of a nuclear chain reaction.

The energy released if hydrogen atoms are combined to form $^{4}_{2}He$ is . . . . . . MeV. (Take binding energies per nucleon of $^{2}H$ and $^{4}_{2}He$ as $1.1$ MeV and $7.2$ MeV, respectively)