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(D) According to Mendel's Law of Dominance,when a cross is made between two pure-breeding parents for two contrasting traits (dihybrid cross),the $F_1

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All yellow round

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(D) According to Mendel's Law of Dominance,when a cross is made between two pure-breeding parents for two contrasting traits (dihybrid cross),the $F_1$ generation expresses only the dominant traits.In this case,yellow color $(Y)$ is dominant over green $(y)$,and round shape $(R)$ is dominant over wrinkled $(r)$.The cross is $YYRR 	imes yyrr$.The gametes produced by $YYRR$ are $YR$,and those by $yyrr$ are $yr$.Upon fertilization,the $F_1$ progeny will have the genotype $YyRr$.Since $Y$ and $R$ are dominant,all $F_1$ individuals will exhibit the yellow round phenotype.

In an experiment on pea plant,pure plants with yellow round seeds $(YYRR)$ were crossed with plants producing green wrinkled seeds $(yyrr)$. What will be the phenotypic ratio of $F_1$ progeny?

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In Mendel's pea plants,round seeds $(RR)$ are dominant over wrinkled seeds $(rr)$,and yellow cotyledons $(YY)$ are dominant over green cotyledons $(yy)$. What will be the phenotypic ratio in the $F_2$ generation of a cross between $RRYY$ and $rryy$?

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In a dihybrid cross where two parents differ in their traits,such as yellow seeds $(YY)$ with round shape $(RR)$ and green seeds $(yy)$ with wrinkled shape $(rr)$,how many seeds out of the total $16$ in the $F_2$ generation will be green $(yy)$?

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