In any Bohr orbit of a hydrogen atom,the rati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an electron revolving in a Bohr orbit of a hydrogen atom at a distance $r$ from the nucleus:Kinetic energy $(K.E.)$ is given by $K = \frac{1}{

Vedclass · Accepted Answer

$-\frac{1}{2}$

Vedclass · Answer

(D) For an electron revolving in a Bohr orbit of a hydrogen atom at a distance $r$ from the nucleus:Kinetic energy $(K.E.)$ is given by $K = \frac{1}{4 \pi \epsilon_{0}} \cdot \frac{e^{2}}{2r} = \frac{e^{2}}{8 \pi \epsilon_{0} r}$.Potential energy $(P.E.)$ is given by $P = -\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{e^{2}}{r}$.Taking the ratio of $K.E.$ to $P.E.$:$\frac{K}{P} = \frac{\frac{e^{2}}{8 \pi \epsilon_{0} r}}{-\frac{e^{2}}{4 \pi \epsilon_{0} r}} = -\frac{4 \pi \epsilon_{0} r}{8 \pi \epsilon_{0} r} = -\frac{1}{2}$.

In any Bohr orbit of a hydrogen atom,the ratio of $K.E.$ to $P.E.$ of a revolving electron at a distance $r$ from the nucleus is:

Similar Questions

Find the energy of the third stationary orbit of Bohr's model of the hydrogen atom if the energy of the ground state is $-E \text{ J}$.

Assertion : Bohr had to postulate that the electrons in stationary orbits around the nucleus do not radiate.
Reason : According to classical physics all moving electrons radiate.

An electron is revolving in $n = 3$ orbit. What will be the magnetic field at the centre of the hydrogen atom? (in $T$)

The angular momentum for the electron in the first Bohr orbit is $L$. If the electron is assumed to revolve in the second orbit of a hydrogen atom,then the change in angular momentum will be:

If the de-Broglie wavelength of an electron in the first Bohr orbit is $\lambda$,then the minimum radial distance between the electrons in the first and second Bohr orbits is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module