In the $AP: 10, 5, 0, -5, \ldots$,the common difference $d$ is equal to $5$. Justify whether the above statement is true or false.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(B) The common difference $d$ of an $AP$ is calculated as $d = a_{n} - a_{n-1}$.
For the given $AP: 10, 5, 0, -5, \ldots$:
$a_{2} - a_{1} = 5 - 10 = -5$
$a_{3} - a_{2} = 0 - 5 = -5$
$a_{4} - a_{3} = -5 - 0 = -5$
Since the difference between consecutive terms is constant,the given list of numbers forms an $AP$ with a common difference $d = -5$.
Therefore,the statement that the common difference $d$ is equal to $5$ is false.

Explore More

Similar Questions

In each of the following,$a$ and $d$ for an $A.P.$ are given. Find the $A.P.$ in each case. $a = \frac{15}{2}, \quad d = \frac{3}{2}$

For the $AP: \frac{3}{2}, \frac{1}{2}, -\frac{1}{2}, -\frac{3}{2}, \ldots,$ write the first term $a$ and the common difference $d$.

Are $-\frac{1}{2}, -\frac{1}{2}, -\frac{1}{2}, -\frac{1}{2}, \ldots$ in an $AP$? If they form an $AP$,find the common difference $d$ and write three more terms.

Difficult
View Solution

Does the sequence $-2, 2, -2, 2, -2, \ldots$ form an $AP$? If it forms an $AP$,write the next two terms.

Verify that each of the following is an $AP$,and then write its next three terms.
$\sqrt{3}, 2 \sqrt{3}, 3 \sqrt{3}, \ldots$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo