In the circuit shown, what will be the curren | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine if the Zener diode is in breakdown, we first calculate the voltage across the parallel combination of the $1 k\Omega$ resistor and th

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(D) To determine if the Zener diode is in breakdown, we first calculate the voltage across the parallel combination of the $1 k\Omega$ resistor and the Zener diode without the Zener diode connected.Using the voltage divider rule, the voltage $V_{AB}$ across the $1 k\Omega$ resistor is:$V_{AB} = V_s 	imes \frac{R_{parallel}}{R_s + R_{parallel}} = 10 V 	imes \frac{1 k\Omega}{1 k\Omega + 1 k\Omega} = 10 V 	imes \frac{1}{2} = 5 V$.Since the voltage across the terminals $A$ and $B$ is $5 V$, which is less than the Zener breakdown voltage of $6 V$, the Zener diode does not conduct.Therefore, the current through the Zener diode is $0 A$ (Zero).

In the circuit shown, what will be the current through the $6 V$ zener diode?

Similar Questions

Mention the use of a Zener diode.

In a Zener regulated power supply, a Zener diode with $V_z = 6 \, V$ is used for regulation. The load current is $4 \, mA$ and the unregulated input voltage is $10 \, V$. To get a Zener current five times the load current, the value of the series resistor $R_S$ is nearly:

Consider the following statements $(A)$ and $(B)$ and identify the correct answer.
$(A)$ $A$ Zener diode is connected in reverse bias when used as a voltage regulator.
$(B)$ The potential barrier of a $p-n$ junction typically lies between $0.1 \, V$ to $0.3 \, V$.

$A$ Zener diode is used for

Vedclass Test Series

Exam Paper Generator

Online Exam Module