In the electronic structure of H_2SO_4,the to | vedclass

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Question

(B) The total number of valence electrons in $H_2SO_4$ is calculated as: $2 	imes (H) + 1 	imes (S) + 4 	imes (O) = 2 	imes 1 + 6 + 4 	imes 6 = 3

Vedclass · Accepted Answer

$16$

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(B) The total number of valence electrons in $H_2SO_4$ is calculated as: $2 	imes (H) + 1 	imes (S) + 4 	imes (O) = 2 	imes 1 + 6 + 4 	imes 6 = 32$ electrons. In the Lewis structure of $H_2SO_4$,there are $8$ covalent bonds (two $S-OH$ bonds,two $S=O$ bonds). Each covalent bond consists of $2$ shared electrons,so the total number of shared electrons is $8 	imes 2 = 16$. The number of unshared electrons (lone pair electrons) is the total valence electrons minus the shared electrons: $32 - 16 = 16$. Thus,the total number of unshared electrons is $16$. Hence,the correct option is $B$.

List-$I$	List-$II$
$(1)$ Hydrogen bond	$(A)$ ${\rm{C}}$
$(2)$ Resonance	$(B)$ ${\rm{LiF}}$
$(3)$ Ionic solid	$(C)$ ${\rm{H}}_2$
$(4)$ Covalent solid	$(D)$ ${\rm{HF}}$
	$(E)$ ${\rm{O}}_3$

List-$I$ (Molecule Species)	List-$II$ (Property/Shape)
$A$. $SO_2Cl_2$	$I$. Paramagnetic
$B$. $NO$	$II$. Diamagnetic
$C$. $NO_2^-$	$III$. Tetrahedral
$D$. $I_3^-$	$IV$. Linear

In the electronic structure of $H_2SO_4$,the total number of unshared electrons is

Similar Questions

Match the items in List-$I$ with the appropriate examples in List-$II$.

List-$I$ List-$II$

$(1)$ Hydrogen bond $(A)$ ${\rm{C}}$

$(2)$ Resonance $(B)$ ${\rm{LiF}}$

$(3)$ Ionic solid $(C)$ ${\rm{H}}_2$

$(4)$ Covalent solid $(D)$ ${\rm{HF}}$

$(E)$ ${\rm{O}}_3$

Match List-$I$ with List-$II$ :

List-$I$ (Molecule Species) List-$II$ (Property/Shape)

$A$. $SO_2Cl_2$ $I$. Paramagnetic

$B$. $NO$ $II$. Diamagnetic

$C$. $NO_2^-$ $III$. Tetrahedral

$D$. $I_3^-$ $IV$. Linear

Choose the correct answer from the options given below :

Identify a molecule with an incomplete octet from the following.

Each of the following compounds contains $p\pi -d\pi$ bonds except:

$XeF_4$ has a total of $36$ valence electrons. Select the correct statement regarding the use of valence electrons in $XeF_4$.

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