In the given circuit,when S_1 is closed,the c | vedclass

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(C) When $S_1$ is closed,the capacitor $C$ is charged to a potential difference $V$. The energy stored in the capacitor is $U_E = \frac{1}{2}CV^2$.Whe

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the instantaneous current in the circuit may be $V\sqrt{\frac{C}{L}}$.

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(C) When $S_1$ is closed,the capacitor $C$ is charged to a potential difference $V$. The energy stored in the capacitor is $U_E = \frac{1}{2}CV^2$.When $S_1$ is opened and $S_2$ is closed,the capacitor $C$ and inductor $L$ form an $LC$ oscillating circuit.The energy oscillates between the electric field of the capacitor and the magnetic field of the inductor.The maximum current $I_{max}$ in the circuit occurs when all the electric energy is converted into magnetic energy.By the law of conservation of energy:$\frac{1}{2}CV^2 = \frac{1}{2}LI_{max}^2$$I_{max}^2 = \frac{C}{L}V^2$$I_{max} = V\sqrt{\frac{C}{L}}$Thus,the instantaneous current in the circuit can reach this maximum value.

In the given circuit,when $S_1$ is closed,the capacitor gets fully charged. Now $S_1$ is opened and $S_2$ is closed. Then

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