In the given figure,if $AB \parallel CD$,$\angle PCD = 130^{\circ}$ and $\angle PBA = 140^{\circ}$,then find $\angle BPC$. (in $^{\circ}$)

  • A
    $50$
  • B
    $90$
  • C
    $80$
  • D
    $40$

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