In the reactionHC equiv CH xrightarrow[(ii) C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Acetylene $(HC \equiv CH)$ reacts with $NaNH_2$ in liquid $NH_3$ to form the acetylide ion $(HC \equiv C^-Na^+)$,which then undergoes $S

Vedclass · Accepted Answer

$X = 1-$butyne,$Y = 3-$hexyne

Vedclass · Answer

(B) Step $1$: Acetylene $(HC \equiv CH)$ reacts with $NaNH_2$ in liquid $NH_3$ to form the acetylide ion $(HC \equiv C^-Na^+)$,which then undergoes $S_N2$ reaction with $CH_3CH_2Br$ to form $1-$butyne $(X = CH_3CH_2C \equiv CH)$.Step $2$: $1-$butyne $(CH_3CH_2C \equiv CH)$ reacts with $NaNH_2$ in liquid $NH_3$ to form the butynylide ion $(CH_3CH_2C \equiv C^-Na^+)$,which then undergoes $S_N2$ reaction with $CH_3CH_2Br$ to form $3-$hexyne $(Y = CH_3CH_2C \equiv CCH_2CH_3)$.

In the reaction
$HC \equiv CH \xrightarrow[(ii) CH_3CH_2Br]{(i) NaNH_2 / liq. NH_3} X$
$\xrightarrow[(ii) CH_3CH_2Br]{(i) NaNH_2 / liq. NH_3} Y$
$X$ and $Y$ are

Similar Questions

By heating a mixture of $CHCl_3$ with silver powder,the compound formed is

When iodoform is heated with $Ag$ powder,the product formed is:

Addition of $HCN$ to ethyne in the presence of $Ba(CN)_2$ as a catalyst gives:

Propyne on hydration in the presence of $H_2SO_4$ and $HgSO_4$ gives:

$C_2H_5-C \equiv C-C_2H_5$ $\xrightarrow{Na/liq. NH_3} (A)$ $\xrightarrow{Br_2/CCl_4} (B)$
Which statement is correct regarding product $(B)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the reaction$HC \equiv CH \xrightarrow[(ii) CH_3CH_2Br]{(i) NaNH_2 / liq. NH_3} X$$\xrightarrow[(ii) CH_3CH_2Br]{(i) NaNH_2 / liq. NH_3} Y$$X$ and $Y$ are