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(B) According to the first law of thermodynamics,the change in internal energy $\Delta U$ is given by $\Delta U = Q + W$,where $Q$ is the heat added t

Vedclass · Accepted Answer

$48$

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(B) According to the first law of thermodynamics,the change in internal energy $\Delta U$ is given by $\Delta U = Q + W$,where $Q$ is the heat added to the system and $W$ is the work done on the system.Given that the gas releases $30 \ J$ of heat,$Q = -30 \ J$.Since $18 \ J$ of work is done on the gas,$W = +18 \ J$.Therefore,the change in internal energy is $\Delta U = -30 \ J + 18 \ J = -12 \ J$.The change in internal energy is defined as $\Delta U = U_f - U_i$,where $U_f$ is the final internal energy and $U_i$ is the initial internal energy.Given $U_i = 60 \ J$,we have $U_f - 60 \ J = -12 \ J$.Solving for $U_f$,we get $U_f = 60 \ J - 12 \ J = 48 \ J$.

In a thermodynamic process,the pressure of a fixed mass of gas is changed in such a manner that the gas releases $30 \ J$ of heat and $18 \ J$ of work is done on the gas. If the initial internal energy of the gas was $60 \ J$,then the final internal energy will be ..... $J$.

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