In which figure,the junction diode is forward | vedclass

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(B) junction diode is forward biased when the potential at the $P$-terminal $(V_P)$ is higher than the potential at the $N$-terminal $(V_N)$,i.e.,$V_P

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(B) junction diode is forward biased when the potential at the $P$-terminal $(V_P)$ is higher than the potential at the $N$-terminal $(V_N)$,i.e.,$V_P > V_N$.Let us analyze each option:$A$: $V_P = +5 \ V$,$V_N = +10 \ V$. Here $V_P $B$: $V_P = -1.0 \ V$,$V_N = -1.5 \ V$. Here $V_P > V_N$ (since $-1.0 > -1.5$),so it is forward biased.$C$: $V_P = 0 \ V$,$V_N = +1 \ V$. Here $V_P $D$: $V_P = -2 \ V$,$V_N = 0 \ V$. Here $V_P Therefore,the correct option is $B$.

In which figure,the junction diode is forward biased?

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