In which of the following situations,does the | vedclass

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(B) We know that if a principal amount $P$ is deposited at $r \%$ compound interest per annum for $n$ years,the amount after $n$ years is given by $A

Vedclass · Accepted Answer

No,it does not form an $A$.$P$. because the difference between consecutive terms is not constant.

Vedclass · Answer

(B) We know that if a principal amount $P$ is deposited at $r \%$ compound interest per annum for $n$ years,the amount after $n$ years is given by $A = P(1 + \frac{r}{100})^n$.For the given problem,$P = 10000$ and $r = 8$.The amount in the account after each year is:Year $1$: $10000(1 + \frac{8}{100})^1 = 10800$Year $2$: $10000(1 + \frac{8}{100})^2 = 11664$Year $3$: $10000(1 + \frac{8}{100})^3 = 12597.12$The sequence of amounts is $10800, 11664, 12597.12, \dots$To check if this is an Arithmetic Progression $(A.P.)$,we calculate the common difference:$d_1 = 11664 - 10800 = 864$$d_2 = 12597.12 - 11664 = 933.12$Since $d_1 
eq d_2$,the difference between consecutive terms is not constant. Therefore,this list of numbers does not form an $A.P.$

In which of the following situations,does the list of numbers involved make an arithmetic progression,and why? The amount of money in the account every year,when ₹ $10000$ is deposited at compound interest at $8 \%$ per annum.

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