Is $0$ a term of the $AP : 31, 28, 25, \ldots ?$ Justify your answer.

(N/A) Let $0$ be the $n^{th}$ term of the given $AP$,i.e.,$a_n = 0$.
Given that,the first term $a = 31$ and the common difference $d = 28 - 31 = -3$.
The $n^{th}$ term of an $AP$ is given by the formula:
$a_n = a + (n - 1)d$
Substituting the values:
$0 = 31 + (n - 1)(-3)$
Rearranging the terms:
$3(n - 1) = 31$
$n - 1 = \frac{31}{3}$
$n = \frac{31}{3} + 1 = \frac{34}{3} = 11 \frac{1}{3}$
Since $n$ must be a positive integer (representing the position of a term),and $11 \frac{1}{3}$ is not an integer,$0$ is not a term of the given $AP$.