Let X = { 1, 2, 3, 4, 5 } and Y = { 1, 3, 5, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) relation from $X$ to $Y$ is a subset of the Cartesian product $X 	imes Y$.For $R_1$: If $x=1, y=3 \in Y$; $x=2, y=4 
otin Y$; $x=3, y=5 \in Y$;

Vedclass · Accepted Answer

Both $(B)$ and $(C)$

Vedclass · Answer

(D) relation from $X$ to $Y$ is a subset of the Cartesian product $X 	imes Y$.For $R_1$: If $x=1, y=3 \in Y$; $x=2, y=4 
otin Y$; $x=3, y=5 \in Y$; $x=4, y=6 
otin Y$; $x=5, y=7 \in Y$. Since $y$ must be in $Y$ for all $x \in X$,$R_1$ is not a relation from $X$ to $Y$ because it contains pairs where $y 
otin Y$.For $R_2$: All pairs $(x, y)$ satisfy $x \in X$ and $y \in Y$. Thus,$R_2 \subseteq X 	imes Y$,so it is a relation.For $R_3$: All pairs $(x, y)$ satisfy $x \in X$ and $y \in Y$. Thus,$R_3 \subseteq X 	imes Y$,so it is a relation.Therefore,both $(B)$ and $(C)$ are relations from $X$ to $Y$.

Let $X = \{ 1, 2, 3, 4, 5 \}$ and $Y = \{ 1, 3, 5, 7, 9 \}$. Which of the following is/are relations from $X$ to $Y$?

Similar Questions

Given $n(U) = 20$,$n(A) = 12$,$n(B) = 9$,$n(A \cap B) = 4$,where $U$ is the universal set,$A$ and $B$ are subsets of $U$,then $n((A \cup B)^C) = $

Write down the power set of $A = \{8, 9\}$.

Given the sets $A = \{1, 2, 3\}$,$B = \{3, 4\}$,and $C = \{4, 5, 6\}$,then $A \cup (B \cap C)$ is:

If $A = \{x : f(x) = 0\}$ and $B = \{x : g(x) = 0\}$,then $A \cap B$ will be

Let $f:R \to R$ be defined by $f(x) = 2x + |x|$,then $f(2x) + f(-x) - f(x) = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module