Let P(-1, 0),Q(0, 0),and R(3, 3sqrt{3}) be th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The slope of $QP$ is $0$ (since $P$ and $Q$ lie on the $x$-axis,specifically the negative $x$-axis).The slope of $QR$ is $\frac{3\sqrt{3} - 0}{3 -

Vedclass · Accepted Answer

$\sqrt{3}x + y = 0$

Vedclass · Answer

(C) The slope of $QP$ is $0$ (since $P$ and $Q$ lie on the $x$-axis,specifically the negative $x$-axis).The slope of $QR$ is $\frac{3\sqrt{3} - 0}{3 - 0} = \sqrt{3}$.This means the angle made by $QR$ with the positive $x$-axis is $60^\circ$.Since $QP$ lies along the negative $x$-axis,the angle $\angle PQR$ is $180^\circ - 60^\circ = 120^\circ$.The angle bisector of $\angle PQR$ will make an angle of $120^\circ - 60^\circ = 60^\circ$ with $QP$ (the negative $x$-axis).Thus,the angle made by the bisector with the positive $x$-axis is $180^\circ - 60^\circ = 120^\circ$.The equation of a line passing through the origin $(0, 0)$ with slope $m = 	an(120^\circ) = -\sqrt{3}$ is $y = -\sqrt{3}x$,which simplifies to $\sqrt{3}x + y = 0$.

Let $P(-1, 0)$,$Q(0, 0)$,and $R(3, 3\sqrt{3})$ be three points. Then the equation of the bisector of the angle $\angle PQR$ is

Similar Questions

The obtuse angle between the lines $y = -2$ and $y = x + 2$ is ....$^o$

Which of the following substances is the most acidic?

The total number of atomic orbitals in the fourth energy level of an atom is .......

To convert a galvanometer into a voltmeter,one should connect a

$A$ frictionless track $ABCDE$ ends in a circular loop of radius $R$. $A$ body slides down the track from point $A$ which is at a height $h = 5 \, cm$. The maximum value of $R$ for the body to successfully complete the loop is .................. $cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module