Let the sum of the maximum and the minimum values of the function $f(x) = \frac{2x^2 - 3x + 8}{2x^2 + 3x + 8}$ be $\frac{m}{n}$,where $\gcd(m, n) = 1$. Then $m + n$ is equal to :

  • A
    $182$
  • B
    $217$
  • C
    $195$
  • D
    $201$

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$(A)$ The minimum value of $g(x)$ is $2^{7/6}$
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