Match the column for molecular shape?

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Question

(B) The molecular shapes are determined by $VSEPR$ theory:
$(a) \ XeO_6^{4-}$ has $6$ bonding pairs and $0$ lone pairs,resulting in an Octahedral sha

Vedclass · Accepted Answer

$a-S, b-Q, c-P, d-R$

Vedclass · Answer

(B) The molecular shapes are determined by $VSEPR$ theory:
$(a) \ XeO_6^{4-}$ has $6$ bonding pairs and $0$ lone pairs,resulting in an Octahedral shape $(S)$.
$(b) \ ClO_2$ has $1$ lone pair and $2$ bond pairs on the central $Cl$ atom,resulting in a $V$-shape $(Q)$.
$(c) \ NH_4^+$ has $4$ bonding pairs and $0$ lone pairs,resulting in a Tetrahedral shape $(P)$.
$(d) \ XeO_3F_2$ has $5$ bonding pairs and $0$ lone pairs,resulting in a Trigonal Bipyramidal shape $(R)$.
Therefore,the correct matching is $a-S, b-Q, c-P, d-R$.

Column $I$	Column $II$
$(a) \ XeO_6^{4-}$	$(P)$ Tetrahedral
$(b) \ ClO_2$	$(Q) \ V\text{-shape}$
$(c) \ NH_4^+$	$(R)$ Trigonal Bipyramidal
$(d) \ XeO_3F_2$	$(S)$ Octahedral

List-$I$ (Shape)	List-$II$ (Molecules)
$A$. $T$-shaped	$I$. $XeF_4$
$B$. Trigonal planar	$II$. $SF_4$
$C$. Square planar	$III$. $ClF_3$
$D$. See-saw	$IV$. $BF_3$

Match the column for molecular shape?

Column $I$ Column $II$

$(a) \ XeO_6^{4-}$ $(P)$ Tetrahedral

$(b) \ ClO_2$ $(Q) \ V\text{-shape}$

$(c) \ NH_4^+$ $(R)$ Trigonal Bipyramidal

$(d) \ XeO_3F_2$ $(S)$ Octahedral

Similar Questions

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Match the column for molecular shape? Column $I$ Column $II$ $(a) \ XeO_6^{4-}$ $(P)$ Tetrahedral $(b) \ ClO_2$ $(Q) \ V\text{-shape}$ $(c) \ NH_4^+$ $(R)$ Trigonal Bipyramidal $(d) \ XeO_3F_2$ $(S)$ Octahedral