Number of compounds from the following which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The compounds are analyzed for their solubility in cold $NaHCO_3$,cold $NaOH$,and hot $NaOH$:$1$. $p$-Toluic acid: Dissolves in $NaHCO_3$ and $NaO

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(D) The compounds are analyzed for their solubility in cold $NaHCO_3$,cold $NaOH$,and hot $NaOH$:$1$. $p$-Toluic acid: Dissolves in $NaHCO_3$ and $NaOH$.$2$. Methyl benzoate: Does not dissolve in cold $NaHCO_3$ or $NaOH$,but undergoes hydrolysis in hot $NaOH$ to form benzoic acid and methanol,thus dissolving.$3$. $p$-Cresyl acetate: Does not dissolve in cold $NaHCO_3$ or $NaOH$,but undergoes hydrolysis in hot $NaOH$ to form $p$-cresol and acetic acid,thus dissolving.$4$. $o$-Hydroxyacetophenone: Dissolves in $NaOH$ (phenolic group) but not $NaHCO_3$.$5$. $3$-Hydroxy$-5-$methylbenzaldehyde: Dissolves in $NaOH$ (phenolic group) but not $NaHCO_3$.$6$. $1$-Isopropyl$-3-$methoxybenzene: Does not dissolve in any of these.$7$. Phenyl acetate: Does not dissolve in cold $NaHCO_3$ or $NaOH$,but undergoes hydrolysis in hot $NaOH$ to form phenol and acetic acid,thus dissolving.Therefore,the compounds that do not dissolve in cold $NaHCO_3$ and $NaOH$ but dissolve in hot $NaOH$ are $2$,$3$,and $7$. The total count is $3$.

Number of compounds from the following which will not dissolve in cold $NaHCO_3$ and $NaOH$ solutions but will dissolve in hot $NaOH$ solution is $........$.

Similar Questions

$(x) \ C_4H_7OCl$ $\xrightarrow{NH_3} C_4H_9ON$ $\xrightarrow[KOH]{Br_2} CH_3-CH_2-CH_2-NH_2$. Compound $x$ is

What are the organic products formed in the following reaction?
$C_6H_5-COOCH_3$ $\xrightarrow{1. LiAlH_4}$ $\xrightarrow{2. H_2O}$

What is the correct order of increasing acidic strength for the following compounds?
$I. CH_3CO_2H$
$II. MeOCH_2CO_2H$
$III. CF_3CO_2H$
$IV. (CH_3)_2CHCO_2H$

The product $P$ in the following reaction is:
$PhCHO + (CH_3CH_2CO)_2O \xrightarrow{CH_3CH_2COONa \text{ (anhydrous)}} P$

An acyl halide is formed when $PCl_5$ reacts with an

Vedclass Test Series

Exam Paper Generator

Online Exam Module