Obtain the ratio of maximum acceleration and maximum velocity of a $SHM$ particle.

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(D) For a particle executing $SHM$ with amplitude $A$ and angular frequency $\omega$,the displacement is given by $x(t) = A \sin(\omega t + \phi)$.
The velocity is $v(t) = \frac{dx}{dt} = A\omega \cos(\omega t + \phi)$. The maximum velocity is $v_{max} = A\omega$.
The acceleration is $a(t) = \frac{dv}{dt} = -A\omega^2 \sin(\omega t + \phi)$. The maximum acceleration is $a_{max} = A\omega^2$.
The ratio of maximum acceleration to maximum velocity is $\frac{a_{max}}{v_{max}} = \frac{A\omega^2}{A\omega} = \omega$.

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$Assertion :$ In simple harmonic motion,the velocity is maximum when the acceleration is minimum.
$Reason :$ Displacement and velocity of $S.H.M.$ differ in phase by $\frac{\pi }{2}$.

Phase space diagrams are useful tools in analyzing all kinds of dynamical problems. They are especially useful in studying the changes in motion as initial position and momentum are changed. Here we consider some simple dynamical systems in one-dimension. For such systems, phase space is a plane in which position is plotted along the horizontal axis and momentum is plotted along the vertical axis. The phase space diagram is the $x(t)$ vs. $p(t)$ curve in this plane. The arrow on the curve indicates the time flow. For example, the phase space diagram for a particle moving with constant velocity is a straight line as shown in the figure. We use the sign convention in which position or momentum upwards (or to the right) is positive and downwards (or to the left) is negative.
$1.$ The phase space diagram for a ball thrown vertically up from the ground is:
$2.$ The phase space diagram for simple harmonic motion is a circle centered at the origin. In the figure, the two circles represent the same oscillator but for different initial conditions, and $E_1$ and $E_2$ are the total mechanical energies respectively. Then:
$(A) E_1 = \sqrt{2} E_2$
$(B) E_1 = 2 E_2$
$(C) E_1 = 4 E_2$
$(D) E_1 = 16 E_2$
$3.$ Consider the spring-mass system, with the mass submerged in water, as shown in the figure. The phase space diagram for one cycle of this system is:
Give the answer for questions $1, 2,$ and $3.$

For a particle executing simple harmonic motion, match the following statements (conditions) from Column-$I$ to statements (shapes of graph) in Column-$II$.
Column-$I$Column-$II$
$(A)$ Velocity-displacement graph $(\omega \neq 1)$$(i)$ Straight line
$(B)$ Acceleration-displacement graph$(ii)$ Sinusoidal
$(C)$ Acceleration-time graph$(iii)$ Circle
$(D)$ Acceleration-velocity graph $(\omega \neq 1)$$(iv)$ Ellipse

An oscillator of mass $M$ is at rest in its equilibrium position in a potential $V = \frac{1}{2}k(x - X)^2$. $A$ particle of mass $m$ comes from the right with speed $u$ and collides completely inelastically with $M$ and sticks to it. This process repeats every time the oscillator crosses its equilibrium position. The amplitude of oscillations after $13$ collisions is: $(M = 10, m = 5, u = 1, k = 1)$.

Match the following physical quantities for a particle executing Simple Harmonic Motion $(SHM)$ given by $y = A \sin(\omega t)$:
$(a)$ Velocity $(v)$
$(b)$ Potential Energy $(PE)$
$(c)$ Total Energy $(TE)$
$(d)$ Acceleration $(a)$
$(i)$ Constant
(ii) $A\omega \cos(\omega t)$
(iii) $\frac{1}{2} k A^2 \sin^2(\omega t)$
(iv) $-\omega^2 y$

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