On increasing the number of electrons striking the anode of an $X-$ray tube,which one of the following parameters of the resulting $X-$rays would increase?

$X$-rays are produced by accelerating electrons through a potential difference $V$ and letting them strike a metal target of atomic number $Z$. The highest frequency of the $X$-rays produced is proportional to:

The diagram shows a graph between the intensity of $X$-rays emitted by a molybdenum target and the wavelength,when electrons of $30 \ keV$ are incident on the target. In the graph,one peak corresponds to the $K_\alpha$ line and the other peak corresponds to the $K_\beta$ line.

The potential difference applied to an $X$-ray tube is increased. As a result,in the emitted radiation

$X$-rays are produced due to which of the following?

The energy of $X$-rays with a wavelength of $1.65 \, \mathring{A}$ is ............. $keV$ (Given: $h = 6.6 \times 10^{-34} \, J \cdot s$,$c = 3 \times 10^{8} \, m/s$,$1 \, eV = 1.6 \times 10^{-19} \, J$). (in $.5$)