One side and one diagonal of a parallelogram are represented by $3 \hat{i}+\hat{j}-\hat{k}$ and $2 \hat{i}+\hat{j}-2 \hat{k}$ respectively. Then,the area of the parallelogram in square units is:

  • A
    $2 \sqrt{3}$
  • B
    $3 \sqrt{2}$
  • C
    $6 \sqrt{2}$
  • D
    $4 \sqrt{3}$

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