The pair of equations 2x + 6y = 10 and 3x + 9 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given equations are $2x + 6y = 10$ and $3x + 9y - 15 = 0$.Divide the first equation by $2$: $x + 3y = 5$.Divide the second equation by $3$: $x + 3

Vedclass · Accepted Answer

infinitely many solutions

Vedclass · Answer

(B) Given equations are $2x + 6y = 10$ and $3x + 9y - 15 = 0$.Divide the first equation by $2$: $x + 3y = 5$.Divide the second equation by $3$: $x + 3y - 5 = 0$,which implies $x + 3y = 5$.Since both equations represent the same line,the ratio of coefficients is $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} = \frac{1}{1} = \frac{3}{3} = \frac{5}{5}$.Therefore,the pair of equations has infinitely many solutions.

The pair of equations $2x + 6y = 10$ and $3x + 9y - 15 = 0$ has..........

Similar Questions

Which of the following pairs of linear equations are consistent/inconsistent? If consistent,obtain the solution graphically: $x-y=8, 3x-3y=16$.

Two straight paths are represented by the equations $x-3y=2$ and $-2x+6y=5$. Check whether the paths cross each other or not.

Solve the following pair of linear equations in two variables using a graph: $2x - 3y = 5$ and $4x - 6y = -13$.

The solution set of the pair of equations $x+y+1=0$ and $3x+3y+2=0$ is .........

Solve the following pair of linear equations using a graph: $x+y=7$,$5x+2y=20$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module