pH of 10^{-8} M HCl solution is | vedclass

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(D) For a very dilute solution like $10^{-8} \ M \ HCl$, the concentration of $H^{+}$ ions from water cannot be neglected.$H^{+}_{total} = [H^{+}]_{HC

Vedclass · Accepted Answer

greater than $6$, less than $7$

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(D) For a very dilute solution like $10^{-8} \ M \ HCl$, the concentration of $H^{+}$ ions from water cannot be neglected.$H^{+}_{total} = [H^{+}]_{HCl} + [H^{+}]_{H_2O}$$[H^{+}]_{total} = 10^{-8} + 10^{-7} \approx 1.1 	imes 10^{-7} \ M$$pH = -\log[H^{+}]_{total} = -\log(1.1 	imes 10^{-7})$$pH = 7 - \log(1.1) \approx 7 - 0.0414 = 6.9586$Thus, the pH is greater than $6$ and less than $7$.

pH of $10^{-8} \ M \ HCl$ solution is

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