(C) According to Einstein's photoelectric equation,the maximum kinetic energy is given by $K_{max} = hf - \phi$. For the first case: $f_1 = 3f$,$\phi

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(C) According to Einstein's photoelectric equation,the maximum kinetic energy is given by $K_{max} = hf - \phi$. For the first case: $f_1 = 3f$,$\phi = 2hf$,and $v_1 = v$. $\frac{1}{2}mv^2 = 3hf - 2hf = hf$ --- $(1)$ For the second case: $f_2 = 4.25f$,$\phi = 2hf$,and $v_2 = ?$. $\frac{1}{2}mv_2^2 = 4.25hf - 2hf = 2.25hf$ --- $(2)$ Dividing equation $(2)$ by equation $(1)$: $\frac{\frac{1}{2}mv_2^2}{\frac{1}{2}mv^2} = \frac{2.25hf}{hf}$ $\frac{v_2^2}{v^2} = 2.25$ $v_2^2 = 2.25v^2$ $v_2 = \sqrt{2.25}v = 1.5v$.

Class 12 Physics Dual Nature of Radiation and Matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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Photoelectrons are emitted with maximum velocity $v$ when light of frequency $3f$ is incident on a photosensitive material of work function $2hf$. If the frequency of the incident light is $4.25f$,the maximum velocity of the emitted photoelectrons is ($h$ = Planck's constant).

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$0.5v$
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$v$
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$1.5v$
D
$2v$

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Dual Nature of Radiation and Matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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Photoelectrons are emitted with maximum velocity $v$ when light of frequency $3f$ is incident on a photosensitive material of work function $2hf$. If the frequency of the incident light is $4.25f$,the maximum velocity of the emitted photoelectrons is ($h$ = Planck's constant).

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