The work function of a metal is 1.6 times 10^ | vedclass

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(C) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{\max}$ is given by:$K_{\max} = \frac{hc}{\lambda} - W_0$Given:Work f

Vedclass · Accepted Answer

$1.4 	imes 10^{-19} \, J$

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(C) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{\max}$ is given by:$K_{\max} = \frac{hc}{\lambda} - W_0$Given:Work function $W_0 = 1.6 	imes 10^{-19} \, J$Wavelength $\lambda = 6400 \, \mathring{A} = 6400 	imes 10^{-10} \, m$Planck's constant $h = 6.4 	imes 10^{-34} \, Js$Speed of light $c = 3 	imes 10^8 \, m/s$Calculating the energy of the incident photon:$E = \frac{hc}{\lambda} = \frac{6.4 	imes 10^{-34} 	imes 3 	imes 10^8}{6400 	imes 10^{-10}}$$E = \frac{19.2 	imes 10^{-26}}{6.4 	imes 10^{-7}} = 3 	imes 10^{-19} \, J$Now,calculating $K_{\max}$:$K_{\max} = 3 	imes 10^{-19} - 1.6 	imes 10^{-19} = 1.4 	imes 10^{-19} \, J$

The work function of a metal is $1.6 \times 10^{-19} \, J$. When the metal surface is illuminated by light of wavelength $6400 \, \mathring{A}$,the maximum kinetic energy of the emitted photo-electrons will be. (Planck's constant $h = 6.4 \times 10^{-34} \, Js$)

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