The polarising angle for water is $53^\circ 4'$. If light is incident at this angle on the surface of water and reflected, the angle of refraction is:

An unpolarized light beam travelling in air is incident on a medium of refractive index $1.73$ at Brewster's angle. Then

$A$ beam of light $AO$ is incident on a glass slab $(\mu = 1.54)$ in a direction as shown in the figure. The reflected ray $OB$ is passed through a Nicol prism. On viewing through the rotating Nicol prism,we find that $(\tan 57^{\circ} = 1.54)$.

The polarising angle for a transparent medium is $\theta$,and $v$ is the speed of light in that medium. Then the relation between $\theta$ and $v$ is (where $c$ is the velocity of light in air).

The Brewster angle for air to glass transition of light is (Refractive index of glass $= 1.5$).

The angle of incidence at which reflected light is totally polarized for reflection from air to glass (refractive index $n$) is