Potential energy of a satellite having mass m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The potential energy $U$ of a satellite of mass $m$ at a distance $r$ from the center of the Earth is given by $U = -\frac{GMm}{r}$.Here,$r = R_e

Vedclass · Accepted Answer

$ - 0.5 \, mgR_e $

Vedclass · Answer

(A) The potential energy $U$ of a satellite of mass $m$ at a distance $r$ from the center of the Earth is given by $U = -\frac{GMm}{r}$.Here,$r = R_e + h$,where $R_e$ is the radius of the Earth and $h$ is the height of the satellite.Given $h = 6.4 	imes 10^6 \ m$ and $R_e \approx 6.4 	imes 10^6 \ m$,we have $r = R_e + R_e = 2R_e$.Using the relation $g = \frac{GM}{R_e^2}$,we can write $GM = gR_e^2$.Substituting these into the potential energy formula:$U = -\frac{(gR_e^2)m}{2R_e} = -\frac{1}{2}mgR_e = -0.5 \, mgR_e$.

Potential energy of a satellite having mass $m$ and rotating at a height of $6.4 \times 10^6 \ m$ from the Earth's surface is

Similar Questions

$A$ person brings a mass of $1 \ kg$ from infinity to a point $A.$ Initially,the mass was at rest but it moves at a speed of $3 \ m/s$ as it reaches $A.$ The work done by the person on the mass is $-5.5 \ J.$ The gravitational potential at $A$ is $:$ (in $J/kg$)

Write the expression for gravitational potential energy and gravitational potential at the surface of the Earth.

Two particles of mass $m$ and $9m$ are separated by a distance $r$. At a point on the line joining them,the gravitational field is zero. What is the gravitational potential at that point? ($G$ is the universal gravitational constant)

If the gravitational field intensity at a point is given by $E = K/x^3$,what is the gravitational potential at that point?

What is gravitational potential energy? Why is gravitational potential negative,and what does it mean?

Vedclass Test Series

Exam Paper Generator

Online Exam Module