Primary and secondary amines are distinguished by
$(i)$ Hinsberg test
$(ii)$ Carbyl amine test
$(iii)$ Hofmann mustard oil test
$(iv)$ $HNO_2$ test

  • A
    $i$ and $iii$ only
  • B
    $i, ii$ and $iv$ only
  • C
    $i, ii, iii$ and $iv$ only
  • D
    $ii$ and $iii$ only

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Similar Questions

Complete the following reactions:
$(i)$ $C_{6}H_{5}NH_{2} + CHCl_{3} +$ alc. $KOH \rightarrow$
$(ii)$ $C_{6}H_{5}N_{2}Cl + H_{3}PO_{2} + H_{2}O \rightarrow$
$(iii)$ $C_{6}H_{5}NH_{2} + H_{2}SO_{4}$ (conc.) $\rightarrow$
$(iv)$ $C_{6}H_{5}N_{2}Cl + C_{2}H_{5}OH \rightarrow$
$(v)$ $C_{6}H_{5}NH_{2} + Br_{2(aq)} \rightarrow$
$(vi)$ $C_{6}H_{5}NH_{2} + (CH_{3}CO)_{2}O \rightarrow$
$(vii)$ $C_{6}H_{5}N_{2}Cl \xrightarrow[(ii) NaNO_{2}/Cu, \Delta ]{(i) HBF_{4}}$

An organic compound $A$ contains nitrogen and chlorine. It dissolves readily in water to give a solution that turns litmus red. Titration of compound $A$ with standard base indicates that the molecular weight of $A$ is $131 \pm 2$. When a sample of $A$ is treated with aqueous $NaOH$,a liquid separates which contains $N$ but not $Cl$. Treatment of the obtained liquid with nitrous acid followed by phenol gives an orange precipitate. The compound $A$ is:

The product $(C)$ of the following reaction is:

Match each of the compounds in Column $I$ with its characteristic reaction$(s)$ in Column $II$.
Column $I$ Column $II$
$A$. $CH_3CH_2CH_2CN$ $p$. Reduction with $Pd-C/H_2$
$B$. $CH_3CH_2OCOCH_3$ $q$. Reduction with $SnCl_2/HCl$
$C$. $CH_3-CH=CH-CH_2OH$ $r$. Development of foul smell on treatment with chloroform and alcoholic $KOH$
$D$. $CH_3CH_2CH_2CH_2NH_2$ $s$. Reduction with diisobutylaluminium hydride $(DIBAL-H)$
$t$. Alkaline hydrolysis

$A$ trinitro compound,$1,3,5$-tris-($4$-nitrophenyl)benzene,on complete reaction with an excess of $Sn/HCl$ gives a major product,which on treatment with an excess of $NaNO_2/HCl$ at $0^{\circ} C$ provides $P$ as the product. $P$,upon treatment with excess of $H_2O$ at room temperature,gives the product $Q$. Bromination of $Q$ in aqueous medium furnishes the product $R$. The compound $P$ upon treatment with an excess of phenol under basic conditions gives the product $S$.
The molar mass difference between compounds $Q$ and $R$ is $474 \ g \ mol^{-1}$ and between compounds $P$ and $S$ is $172.5 \ g \ mol^{-1}$.
$(1)$ The number of heteroatoms present in one molecule of $R$ is . . . . .
[Use: Molar mass (in $g \ mol^{-1}$): $H=1, C=12, N=14, O=16, Br=80, Cl=35.5$
Atoms other than $C$ and $H$ are considered as heteroatoms]
$(2)$ The total number of carbon atoms and heteroatoms present in one molecule of $S$ . . . . . .
[Use: Molar mass in $g \ mol^{-1}$]: $H=1, C=12, N=14, O=16, Br=80, Cl=35.5$
Atoms other than $C$ and $H$ are considered as heteroatoms
Give the answer for question $(1)$ and $(2)$.

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