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(B) $1$. The starting material is acetophenone. Nitration with $HNO_3/H_2SO_4$ introduces a nitro group at the meta-position due to the deactivating a

Vedclass · Accepted Answer

$3-$ethylaniline

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(B) $1$. The starting material is acetophenone. Nitration with $HNO_3/H_2SO_4$ introduces a nitro group at the meta-position due to the deactivating and meta-directing nature of the acetyl group,forming $3$-nitroacetophenone $(A)$.$2$. The second step involves Clemmensen reduction using $Zn(Hg)/HCl$. This reagent reduces the carbonyl group $(C=O)$ to a methylene group $(CH_2)$.$3$. Importantly,$Zn(Hg)/HCl$ also reduces the nitro group $(NO_2)$ to an amino group $(NH_2)$.$4$. Therefore,the final product $(B)$ is $3$-ethylaniline.

The product $(B)$ of the following reaction is:

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