Rajesh covers a certain distance by bus at 16 | vedclass

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Question

(B) Let the distance covered be $d$. Time taken to travel by bus,$t_1 = \frac{d}{16}$. Time taken to return by cycle,$t_2 = \frac{d}{9}$. Total distan

Vedclass · Accepted Answer

$11.52$

Vedclass · Answer

(B) Let the distance covered be $d$. Time taken to travel by bus,$t_1 = \frac{d}{16}$. Time taken to return by cycle,$t_2 = \frac{d}{9}$. Total distance covered = $d + d = 2d$. Total time taken = $t_1 + t_2 = \frac{d}{16} + \frac{d}{9} = \frac{9d + 16d}{144} = \frac{25d}{144}$. Average speed = $\frac{	ext{Total distance}}{	ext{Total time}} = \frac{2d}{\frac{25d}{144}} = \frac{2 	imes 144}{25} = \frac{288}{25} = 11.52 	ext{ km/h}$. Alternatively,using the formula for average speed when distance is constant: $	ext{Average speed} = \frac{2s_1s_2}{s_1 + s_2} = \frac{2 	imes 16 	imes 9}{16 + 9} = \frac{288}{25} = 11.52 	ext{ km/h}$.

Rajesh covers a certain distance by bus at $16 \text{ km/h}$ and returns to the starting point on a cycle at $9 \text{ km/h}$. His average speed for the whole journey is (in $\text{km/h}$):

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