Reduce the following equation into slope-intercept form and find its slope and the $y$-intercept: $y=0$.

The equation $r \cos \left(\theta-\frac{\pi}{3}\right)=2$ represents

The sum of the squares of the intercepts made by the line $5x - 2y = 10$ on the coordinate axes equals:

The equation of a line is $3x - 4y + 10 = 0$. Find its slope.

The lines $2x + 3y = 6$ and $2x + 3y = 8$ cut the $X$-axis at $A$ and $B$,respectively. $A$ line $L$ drawn through the point $(2, 2)$ meets the $X$-axis at $C$ in such a way that the abscissae of $A, B,$ and $C$ are in arithmetic progression. Then,the equation of the line $L$ is

$A$ line passes through the point $(1, 2)$ and makes an angle of $60^{\circ}$ with the $x$-axis. The coordinates of the points on this line at a distance of $3$ units from the point $(1, 2)$ are: