Resistance of $0.1\, M\, KCl$ solution in a conductance cell is $300\, \Omega$ and conductivity is $0.013\, S\, cm^{-1}$. The value of cell constant is

In a conductivity cell,the electrodes are separated by a distance of $2 \ cm$ and have a cross-sectional area of $4 \ cm^2$. If the conductivity of pure water is $8 \times 10^{-7} \ S \ cm^{-1}$,then the resistance of the water is:

The equivalent conductance of $NaCl$ at concentration $C$ and at infinite dilution are $\lambda_C$ and $\lambda_{\infty}$ respectively. The correct relationship between $\lambda_C$ and $\lambda_{\infty}$ is given as: (Where the constant $B$ is positive)

The limiting molar conductivities $(\Lambda_0)$ for $NaCl$,$KBr$ and $KCl$ are $126$,$152$ and $150 \ S \ cm^2 \ mol^{-1}$ respectively. What is the $\Lambda_0$ of $NaBr$?

What is the molar conductivity of a $0.05 \ M$ solution of sodium hydroxide,if its conductivity is $0.0118 \ S \ cm^{-1}$ at $298 \ K$?

Calculate the molar conductivity of $NH_4OH$ at infinite dilution,given that the molar conductivities of $Ba(OH)_2$,$BaCl_2$,and $NH_4Cl$ are $523.28$,$280.0$,and $129.8 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.