The limiting molar conductivities $(\Lambda_0)$ for $NaCl$,$KBr$ and $KCl$ are $126$,$152$ and $150 \ S \ cm^2 \ mol^{-1}$ respectively. What is the $\Lambda_0$ of $NaBr$?

  • A
    $128 \ S \ cm^2 \ mol^{-1}$
  • B
    $302 \ S \ cm^2 \ mol^{-1}$
  • C
    $278 \ S \ cm^2 \ mol^{-1}$
  • D
    $176 \ S \ cm^2 \ mol^{-1}$

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Similar Questions

Identify True $(T)$ or False $(F)$ for the following statements :
$(i)$ As temperature of solution is more,then conductivity is more.
$(ii)$ Conductivity of $Cu \propto$ temperature.
$(iii)$ As temperature increases,conductivity of $Cu$ decreases.

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Calculate the molar conductivity of a $0.02 \, M$ solution if its conductivity is $2.06 \times 10^{-3} \, S \, cm^{-1}$.

The specific conductance $(k)$ of $0.02 \ M$ aqueous acetic acid solution at $298 \ K$ is $1.65 \times 10^{-4} \ S \ cm^{-1}$. The degree of dissociation $(\alpha)$ of acetic acid is: [Given: $\lambda_{H^{+}}^{\infty} = 349.1 \ S \ cm^2 \ mol^{-1}$ and $\lambda_{CH_3COO^{-}}^{\infty} = 40.9 \ S \ cm^2 \ mol^{-1}$]

The conductivity of $0.3 \ M$ solution of $KCl$ at $298 \ K$ is $0.0627 \ S \ cm^{-1}$. What is its molar conductivity?

The molar conductivity of $KCl$ solutions at different concentrations at $298 \, K$ are given below:
$c^{1/2} / (mol \, L^{-1})^{1/2}$$\Lambda_m / S \, cm^2 \, mol^{-1}$
$0.000198$$148.61$
$0.000309$$148.29$
$0.000521$$147.81$
$0.000989$$147.09$

Show that a plot between $\Lambda_m$ and $c^{1/2}$ is a straight line. Determine the values of $\Lambda_m^o$ and $A$ for $KCl$.

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