Resolve into factors: 16 x^{2}-72 x y+81 y^{2 | vedclass

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Question

(B) Given expression: $16 x^{2}-72 x y+81 y^{2}-12 x+27 y$Observe that the first three terms form a perfect square: $(4 x)^{2}-2(4 x)(9 y)+(9 y)^{2} =

Vedclass · Accepted Answer

$(4 x-9 y)(4 x-9 y-3)$

Vedclass · Answer

(B) Given expression: $16 x^{2}-72 x y+81 y^{2}-12 x+27 y$Observe that the first three terms form a perfect square: $(4 x)^{2}-2(4 x)(9 y)+(9 y)^{2} = (4 x-9 y)^{2}$Now,factor out $-3$ from the remaining two terms: $-12 x+27 y = -3(4 x-9 y)$Combining these,we get: $(4 x-9 y)^{2}-3(4 x-9 y)$Taking $(4 x-9 y)$ as a common factor: $(4 x-9 y)(4 x-9 y-3)$

Resolve into factors: $16 x^{2}-72 x y+81 y^{2}-12 x+27 y$

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