Resolving power of a telescope increases when

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The resolving power $(RP)$ of a telescope is defined as the reciprocal of the minimum angular separation between two objects that can be just dist

Vedclass · Accepted Answer

wavelength of light decreases.

Vedclass · Answer

(A) The resolving power $(RP)$ of a telescope is defined as the reciprocal of the minimum angular separation between two objects that can be just distinguished by the telescope.It is given by the formula:$RP = \frac{D}{1.22 \lambda}$where $D$ is the diameter of the objective lens and $\lambda$ is the wavelength of light used.From the formula,it is clear that $RP \propto \frac{1}{\lambda}$.Therefore,when the wavelength of light $(\lambda)$ decreases,the resolving power of the telescope increases.

Similar Questions

The ratio of resolving powers of an optical microscope for two wavelengths $\lambda_1 = 4000\,\mathring{A}$ and $\lambda_2 = 6000\,\mathring{A}$ is

The resolving power of a microscope depends upon:

By increasing the aperture of the objective lens,how do the wavelength of light,the focal length of the objective lens,and the resolving power of an astronomical telescope change,respectively?

For a given wavelength,telescopes with large aperture objectives are used for:

The resolving power of the human eye is $1'$. At what distance $r$ (in $km$) can two objects separated by a distance of $d = 3 \, m$ be seen as distinct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module