Savita and Hamida are friends. What is the pr | vedclass

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(A) Out of the two friends,one girl,say,Savita's birthday can be any day of the year. Now,Hamida's birthday can also be any day of $365$ days in the y

Vedclass · Accepted Answer

$364/365, 1/365$

Vedclass · Answer

(A) Out of the two friends,one girl,say,Savita's birthday can be any day of the year. Now,Hamida's birthday can also be any day of $365$ days in the year.We assume that these $365$ outcomes are equally likely.$(i)$ If Hamida's birthday is different from Savita's,the number of favourable outcomes for her birthday is $365 - 1 = 364$.So,$P(	ext{Hamida's birthday is different from Savita's birthday}) = \frac{364}{365}$.$(ii)$ $P(	ext{Savita and Hamida have the same birthday})$$= 1 - P(	ext{both have different birthdays})$$= 1 - \frac{364}{365} \quad [	ext{Using } P(\overline{E}) = 1 - P(E)]$$= \frac{1}{365}$.

Savita and Hamida are friends. What is the probability that both will have $(i)$ different birthdays? $(ii)$ the same birthday? (ignoring a leap year).

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