Select the odd one among the following orbita | vedclass

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Question

(C) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of the principal quantum number $(n)$ and the azimuthal quantum nu

Vedclass · Accepted Answer

$3s$

Vedclass · Answer

(C) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of the principal quantum number $(n)$ and the azimuthal quantum number $(l)$.For $4f$: $n=4, l=3$,so $n+l = 4+3 = 7$.For $5d$: $n=5, l=2$,so $n+l = 5+2 = 7$.For $3s$: $n=3, l=0$,so $n+l = 3+0 = 3$.For $6p$: $n=6, l=1$,so $n+l = 6+1 = 7$.Since $3s$ has a different $(n+l)$ value compared to the others,it is the odd one.

Select the odd one among the following orbitals based on the $(n+l)$ rule.

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