Shape of (SiH_3)_3N and (SiH_3)_3P respective | vedclass

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(B) In $(SiH_3)_3N$,the lone pair on $N$ is involved in $p\pi-d\pi$ back-bonding with the empty $d$-orbitals of $Si$. This makes the $N$ atom $sp^2$ h

Vedclass · Accepted Answer

Trigonal planar,Tetrahedral

Vedclass · Answer

(B) In $(SiH_3)_3N$,the lone pair on $N$ is involved in $p\pi-d\pi$ back-bonding with the empty $d$-orbitals of $Si$. This makes the $N$ atom $sp^2$ hybridized,resulting in a trigonal planar geometry.In $(SiH_3)_3P$,the $P$ atom has a lone pair,but the energy gap between the $P$ $3p$ orbital and $Si$ $3d$ orbital is large,making $p\pi-d\pi$ back-bonding ineffective. Thus,$P$ remains $sp^3$ hybridized with a lone pair,resulting in a pyramidal (tetrahedral arrangement of electron pairs) geometry.

Column $I$	Column $II$
$(a) \ XeO_6^{4-}$	$(P)$ Tetrahedral
$(b) \ ClO_2$	$(Q) \ V\text{-shape}$
$(c) \ NH_4^+$	$(R)$ Trigonal Bipyramidal
$(d) \ XeO_3F_2$	$(S)$ Octahedral

Shape of $(SiH_3)_3N$ and $(SiH_3)_3P$ respectively are

Similar Questions

The molecular shapes of $SF_4$, $CF_4$ and $XeF_4$ are

Which of the following is $INCORRECT$?

Match the column for molecular shape?

Column $I$ Column $II$

$(a) \ XeO_6^{4-}$ $(P)$ Tetrahedral

$(b) \ ClO_2$ $(Q) \ V\text{-shape}$

$(c) \ NH_4^+$ $(R)$ Trigonal Bipyramidal

$(d) \ XeO_3F_2$ $(S)$ Octahedral

Which of the following sequences represents the correct increasing order of bond angles in the given molecules?

In the molecule $I_2Cl_6$,choose the $CORRECT$ statement$(s)$.

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