Simplify $(p \vee q) \wedge (p \vee \sim q)$

The statement pattern $p \wedge (q \vee \sim p)$ is equivalent to

The simplest form of the following switching circuit is:

If $(p \wedge \sim q) \wedge r \to \sim r$ is $F$,then the truth value of $r$ is:

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is $False$, then the truth values of $p \to q$ and $q \to p$ are respectively...

The logical expression $p \wedge (\sim p \vee \sim q) =$ ?