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(A) The given quadratic equation is $\sqrt{3}x^{2} - 2x + \sqrt{3} = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = \sqrt{

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No real solution

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(A) The given quadratic equation is $\sqrt{3}x^{2} - 2x + \sqrt{3} = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = \sqrt{3}$,$b = -2$,and $c = \sqrt{3}$.First,we calculate the discriminant $D = b^{2} - 4ac$.$D = (-2)^{2} - 4(\sqrt{3})(\sqrt{3})$$D = 4 - 4(3) = 4 - 12 = -8$.Since the discriminant $D < 0$,the equation has no real roots in the set of real numbers $R$.

Solve the following equation using the quadratic formula,if the equation has a solution in $R$: $\sqrt{3}x^{2} - 2x + \sqrt{3} = 0$

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