Some amount out of ₹7000 was lent at 6 % p.a. | vedclass

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(D) Let the amount lent at $6 \%$ be $x$ and the amount lent at $4 \%$ be $(7000 - x)$.Using the simple interest formula $SI = \frac{P 	imes R 	imes

Vedclass · Accepted Answer

$2000$

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(D) Let the amount lent at $6 \%$ be $x$ and the amount lent at $4 \%$ be $(7000 - x)$.Using the simple interest formula $SI = \frac{P 	imes R 	imes T}{100}$:$\frac{x 	imes 6 	imes 5}{100} + \frac{(7000 - x) 	imes 4 	imes 5}{100} = 1600$$30x + 20(7000 - x) = 160000$$30x + 140000 - 20x = 160000$$10x = 20000$$x = 2000$Alternatively,using the alligation method:Overall rate of interest $= \frac{1600 	imes 100}{7000 	imes 5} = \frac{32}{7} \%$.The ratio of the amounts is $|4 - \frac{32}{7}| : |6 - \frac{32}{7}| = |\frac{28-32}{7}| : |\frac{42-32}{7}| = \frac{4}{7} : \frac{10}{7} = 2 : 5$.Amount lent at $6 \% = \frac{2}{2+5} 	imes 7000 = \frac{2}{7} 	imes 7000 = ₹2000$.

Some amount out of ₹$7000$ was lent at $6 \%$ $p.a.$ and the remaining at $4 \%$ $p.a.$ If the total simple interest from both the fractions in $5$ $years$ was ₹$1600$,the sum lent at $6 \%$ $p.a.$ was (in ₹).

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