State whether each of the following statements is true or false:
$(1)$ In $\Delta XYZ$,if $XY > XZ$,then $\angle Z > \angle Y$.
$(2)$ In $\Delta ABC$ and $\Delta PQR$,if $\frac{AB}{PR} = \frac{BC}{QP} = \frac{CA}{RQ} = 1$,then $\Delta ABC \cong \Delta RPQ$.
$(1)$ In $\Delta XYZ$,if $XY > XZ$,then $\angle Z > \angle Y$.
$(2)$ In $\Delta ABC$ and $\Delta PQR$,if $\frac{AB}{PR} = \frac{BC}{QP} = \frac{CA}{RQ} = 1$,then $\Delta ABC \cong \Delta RPQ$.
(A) $(1)$ False. According to the theorem,in any triangle,the angle opposite to the longer side is larger. Since $XY > XZ$,the angle opposite to $XY$ (which is $\angle Z$) must be greater than the angle opposite to $XZ$ (which is $\angle Y$). Therefore,$\angle Z > \angle Y$.
$(2)$ True. Given $\frac{AB}{PR} = \frac{BC}{QP} = \frac{CA}{RQ} = 1$,it implies $AB = PR$,$BC = QP$,and $CA = RQ$. By the $SSS$ (Side-Side-Side) congruence criterion,$\Delta ABC \cong \Delta RPQ$.
$(2)$ True. Given $\frac{AB}{PR} = \frac{BC}{QP} = \frac{CA}{RQ} = 1$,it implies $AB = PR$,$BC = QP$,and $CA = RQ$. By the $SSS$ (Side-Side-Side) congruence criterion,$\Delta ABC \cong \Delta RPQ$.
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