Statement $1$: The variance of the first $n$ odd natural numbers is $\frac{n^2 - 1}{3}$.
Statement $2$: The sum of the first $n$ odd natural numbers is $n^2$ and the sum of the squares of the first $n$ odd natural numbers is $\frac{n(4n^2 - 1)}{3}$.

  • A
    Statement $1$ is true,Statement $2$ is false.
  • B
    Statement $1$ is true,Statement $2$ is true; Statement $2$ is not a correct explanation for Statement $1$.
  • C
    Statement $1$ is false,Statement $2$ is true.
  • D
    Statement $1$ is true,Statement $2$ is true; Statement $2$ is a correct explanation for Statement $1$.

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Similar Questions

Find the variance and standard deviation for the following data:
$x_i$ $4$ $8$ $11$ $17$ $20$ $24$ $32$
$f_i$ $3$ $5$ $9$ $5$ $4$ $3$ $1$

An analysis of monthly wages paid to workers in two firms $A$ and $B$,belonging to the same industry,gives the following results:
\text{Particulars} \text{Firm } $A$ \text{ and Firm } $B$
\text{No. of wage earners} $A: 586, B: 648$
\text{Mean of monthly wages} $A: Rs. 5253, B: Rs. 5253$
\text{Variance of wages} $A: 100, B: 121$

Which firm,$A$ or $B,$ shows greater variability in individual wages?

Calculate the variance if $\Sigma x_i^2 = 18000$ and $\Sigma x_i = 960$,for $60$ observations.

The mean and the standard deviation of a data set of $8$ items are $25$ and $5$ respectively. If two items $15$ and $25$ are added to this data,then the variance of the new data is:

Let $x_{i} (1 \leq i \leq 10)$ be ten observations of a random variable $X$. If $\sum_{i=1}^{10} (x_{i} - p) = 3$ and $\sum_{i=1}^{10} (x_{i} - p)^{2} = 9$,where $0 \neq p \in R$,then the standard deviation of these observations is:

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